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A long solenoid that has 990 turns uniformly distributed over a length of 0.420 m produces...

A long solenoid that has 990 turns uniformly distributed over a length of 0.420 m produces a magnetic field of magnitude 1.00 10-4 T at its center. What current is required in the windings for that to occur?
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Answer #1


The expression for the magnetic field at the center of the solenoid is, B = H.nl Here, I is the current in the solenoid, n is

Combine n = and B = u ni to solve for I. I = B1 MON (1.0x104T)(0.420m) (47x10- Tom (990) = 33.76x10-A Α =33.76mA

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