Question

.30 kg mass has location x as graphed. label max acceleration, calculate curvature , energy in oscillator

P5. A 0.30 kg mass has location Xı as graphed: a) Label its maximum acceleration “am” compute its maximum acceleration Position (cm) 400 0.1 0.2 0.3 Time (s) 0.4 b) Label its zero speed times as “SO”; Label its zero acceleration times as "a0” c) calculate the PE curvature (stiffness) 0.5 d) calculate the Energy in the oscillator.

Answer 1

a) dt m the graph it is clear the equation x-t relation is a = 2.5 Count : a = dx = :- 215*4 h Sinunt - – lon sinunt. a= dv - (107) (an) casunt - -40 a Cosunt amax = 40x²1 m/s2 at to 4 sec 0.25 DEC. : ve - lot sinunnt only magnitude speed- lu= lot sinunt N1=0=So b) at t=0 & 0.5 sec. 2.-o acceleration a= =dox Cə чи t a-o at ts & 01/25 sec & 0.375 sec . wo k=w²m k - (47) ²0.30 [wouh] 47.32 N/m