(a)
In equilibrium net force = 0
Fb - mg = 0
Fb = m*g
Fb = buoyancy force = rho_water*V*g
V = volume of the sphere = (4/3)*pi*R^3
rho_water*(4/3)*pi*R^3*g = m*g
1000*(4/3)*pi*R^3*9.8 = 0.9860*9.8
radius r = 61.74 mm
=========================
part B
mass = density of copper * volume of copper
volume of copper v = (4/3)*pi*(R^3-r^3)
0.9860 = 8.96*10^3*(4/3)*pi*((61.74*10^-3)^3-r^3)
inner radius of the shell r = 59.35 mm
thickness of the shell = R - r = 2.390 mm
<<<----ANSWER
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