Question
A hollow copper (ρCu = 8.960 ✕ 103 kg/m3) spherical shell of mass m = 0.9860 kg floats in water with its entire volume below the surface. (Assume the temperature of the water is 4°C. Enter your answers to at least four significant figures.)
4 5 points KatzPSEf1 15 P025.MI. My Notes Ask Your Teacher A hollow copper (Cu-8.960 x 103 kg/m3) spherical shell of mass m = 0.9860 kg floats in water with its entire volume below the surface. (Assume the temperature of the water is 4°C. Enter your answers to at least four significant figures.) (a) What is the radius of the sphere? (b) What is the thickness of the shell wall? Need Help? Lenaar. Latter.」
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Answer #1


(a)


In equilibrium net force = 0

Fb - mg = 0

Fb = m*g


Fb = buoyancy force = rho_water*V*g

V = volume of the sphere = (4/3)*pi*R^3


rho_water*(4/3)*pi*R^3*g = m*g

1000*(4/3)*pi*R^3*9.8 = 0.9860*9.8


radius r = 61.74 mm

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part B


mass = density of copper * volume of copper


volume of copper v = (4/3)*pi*(R^3-r^3)

0.9860 = 8.96*10^3*(4/3)*pi*((61.74*10^-3)^3-r^3)


inner radius of the shell r = 59.35 mm


thickness of the shell = R - r = 2.390 mm <<<----ANSWER

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