A 40 ohm resistor and a 60 ohm resistor are connected in series to a 12 volt battery.
A. What is the voltage difference across each resistor?
Current = 12/(40+60) = 12/100 = 0.12 A
A)
Voltage accross 40 ohm = I*R = 0.12*40 = 4.8 V
Voltage accross 60 ohm = I*R = 0.12*60 = 7.2 V
Req = 40 + 60 = 100 Ohm
i = V / Req = 12 / 100 = 0.12 A
A)
Voltage across 40 => 0.12*40 = 4.8 V
Voltage across 60 => 0.12*60 = 7.2 V
If resistors are connected in series them same current flows
Given
R1=40 ohms R2=60 ohms V=12 volts
Now total voltage=V=v1+v2
Total resistance=R=r1+r2=40+60=100 (since they are in series)
Now apply ohms law
V=IR substituting values we get
12=I*100
I=12/100 amperes(total current)
Now v1= voltage across 40 ohms resistor =IR1=(12/100)*40=4.8 volts
V2=voltage across 60 ohms resistor=IR2=(12/100)*60=7.2 volts
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