Question

Problem 4 (28 points). a) (20 points) Using row and column addressing, design a 64 Mb yte memory that is addressable in 4-byte segments (i.e. the data bus consists of 4 bytes) to have as close to a 1:1 aspect ratio possible. As Clearly label the number of rows and columns and address bus. as sume that the physical height of a bit cell equals the physical width of a bit cell

Answer 1

Given that memory size is 64 m B given that data bytes is 4 bytes we know that memory size is given by 2^n times d = memory size here d = data bits n = no of address line 1 M B = 2^20 bits and 1 bytes = 8 bits so 2^n times 4 times 8 = 2^20 times 64 so 2^n = 2^6 times 2^20/2^2 times 2^3 = 2^6 times 2^20/2^5 = 2^21 so 2^n = 2^21 so n = 21 so no of address line (n) = 21 no of rows 2^n = 2^21 no of columns = 4 times 8 = 32