Question

1. Given the table of measurements 54 56 60 58 59 58 59 59 55 60 56 59 57 61 62 58 58 57 57 56 57 55 59 57 60 58 57 58 a. Make a tally histogram b. Make a histogram for the individual measurements. c. Make a grouped histogram with the first group 54 to 55, the second group 56 to 57. etc. d. Find i e. Population standard deviation, assuming i = u f. Sample standard deviation h. 32

Answer 1

Answer: x bar=mean = 37.86 Population Standard deviation=1283 population variance-3.34 Sample Variance = 3.461 Wo Frequency table with tally Mark. - Xi 54 55 56 57 58 59 60 61 6w | Taller i 11 III III II IIII III I I | Toeg i į 3 6 6 5 3 il B. Histogram for the indåvidual measurements:

tuanbalts - {eot so 54 - 55 56 57 58 59 60 61 6h No. of variables Có Make a Histogoam with A-nh, HG hat, 568-69, 60-61, 62-63. Graph. Frequency 154-55 3 56 57 58 59 60-61 Gio 63 q ll 4 → Frequency ' 24-5 h 56 57 58 59 60 61 62 63 -

D: X = Mean N=R8 no- of variables * - Exi = mean Exi=24+ 56+60+58+59+ 58+59 +59 +55+60 + 56+59 +51 +61 +62t h8+18+ h1+ ht+ +6+++-1 69 th7+60+ box +ni+FO8 = Exp=1680 Exp=1680 X = Sxi - 1620 = 10486. Tos Population standard deviation: Jn Exp-xjh C = population - S:D

CX-x) = [LE-40 tỷ - 16+ 1 +6810s (46 +1:30+0 0196+ 1030 103078018+4. +3046+1•30 70-74+9086717014 10.0196 +000196 +0.74 +0.74 +2 046 +0.744 8-18 +1-30+0-Hit 40598 +0.0198 70-74 +0.0196 = ECX9–)® – 93.44 --- 93.44 v 28 = 1334 = 1-83 Hence Population e Standard deviation is 10=1183)

f: Sample standard Distribution 8 = ECxi=3J v net v 27 Ecxp -)=93.44 8 = 93.444 -13-461 = 1686. S = 1-86. Jo a variance of population = CS-D-of population)«–C1-83) Hence W = 3.34 . ho sứ= Sample Variance = C1-8678 tence. =3.461 Sample variance sæ= 3.4611