Question

20. The generator in the diagram has ms voltage 45 V, at angular frequency a 1,000 radis The resistance is R-3.0 ?, and the reactances are x,-6.0 ? und Xe-20a (a) Find L, C, the impedance, the rms current, the phase angle by which the vortag leads/lags the v and the average power L- mH PAV (b) The generator frequency is now re-set to the resonance frequency; the emf is still 45 V, rms. Find the new values of current and phase. I'RMS

Answer 1

Given data: - voltage, v = 45 volts angular frequency, w = 1000 rad/sec Resistance R = 3.0 Ohm inductive Reactance x_L = 6.0 Ohm capacitive Reactance x_L = 2.0 Ohm (a) x_L = w_L x_L = 2 pi fL L = x_L/2 pi f = 6/1000 inductance L = 6 times 10^-3 H x_L = 1/wc x_L = 1/wc c = 1/x_cw = 1/2 times 1000 = 5 times 10^-4 F. (or) capacitance c = 500 mu p Because w = 2 pi f_L w = 2 pi f. \r\n impedance, z = squareroot R^2 7 + x^2 = squareroot R^2 + (x_2 - x^2)^2 = squareroot 3^2 + (6 - 2)^2 = squareroot 3^2 + (47)^2 = squareroot 9 + 16 = squareroot 25 z = 5 Ohm rms current (I_rms) I_rms = v_rms/z = 45/5 I_rms = 9.A Phase angle b/w voltage and current (Phi) Phi = tan^-1