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6. A fruit juice manufacturer claims that on average the vitamin C content of their new...
A cigarette manufacturer claims that the average nicotine content of their new brand XXX is at mo...
A cigarette manufacturer claims that the average nicotine content of their new brand XXX is at most 1.35 mg. It would be unwise to reject the manufacturer's claim without strong contradictory evidence. An appropriate problem formulation is to test A random sample of 100 brand XXX cigarettes are tested and the sample standard deviation and sample mean are found to be 0.07 mg and 1.361 mg, respectively. Assuming the central limit theorem applies and s ≈ σ, find the p-value...
measured concentration of vitamin C in fruit juice. ( mol/L) Type of juice Ppple Volume of...
measured concentration of vitamin C in fruit juice. (
mol/L)
Type of juice Ppple Volume of container: 200mL Volume per serving: aob mL Servings per container: % RDA of vitamin C per serving: 1007 Calculated concentration of vitamin C based on packaging: RDA for vitamin C: 90 mg O.45 mg/mL 2.55X 10o ,mol/L Calculated molar concentration of vitamin C based on packaging: (assume molar mass is equal to that of ascorbic acid, 176.12 g/mol) Titration Data: 0.00Sm Concentration of lodine...
Q1. Q2. Uhom a tion of 0.305. To monitor this Question 13 (1 mark) Attempt 1...
Q1.
Q2.
Uhom a tion of 0.305. To monitor this Question 13 (1 mark) Attempt 1 The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.4. Historically the percentage of SiO2 in the cement is normally distributed w process, periodically an engineer takes a random sample of 16 measurements. A recent sample yielded a sample mean of 5.228 Find the p-value associated with the following hypothesis test. Ho:u=5.4 versus H,: *5.4 Your answer can...
[6-34] The manufacturer of a new fiberglass tire claims that its average life will be at...
[6-34] The manufacturer of a new fiberglass tire claims that its average life will be at least 40,000 miles. To verify this claim, sample of 15 tires are tested. Sample mean was 41.1 (in 1000 miles), and sample standard deviation was 2.50. Assuming the measurements were random sample from a Normal distribution, calculate 95% one-sided confidence interval for true mean tire life. Choose lower-bound or upper-bound, whichever is appropriate. (Round to 2 decimals.) Your Answer: Answer
A local bottler in Hawaii wishes to ensure that an average of 24 ounces of passion...
A local bottler in Hawaii wishes to ensure that an average of 24 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 50 bottles. The mean weight of the passion fruit juice in the sample is 23.69 ounces. Assume that the population standard deviation is 0.87 ounce. . Calculate the value of the test statistic. - Find the p-value. c-1. What is...
1) A manufacturer claims that the mean amount of juice in its 16 ounce bottles is...
1) A manufacturer claims that the mean amount of juice in its 16 ounce bottles is at least 16.1 ounces. C) Two-tailed A) Right-tailed B) Left-tailed 2) A health insurer has determined that the "reasonable and customary" fee for a certain medical procedure is $1200. They suspect that the average fee charged by one particular clinic for this procedure is less than $1200 and wish to conduct a test to see if the suspicion can be supported. B) Left-tailed C)...
Please answer all 3 questions Question 15 1 pts A local juice manufacturer distributes juice in...
Please answer all 3 questions
Question 15 1 pts A local juice manufacturer distributes juice in bottles labeled 12 ounces. A government agency thinks that the company is cheating its customers. The agency selects 50 of these bottles, measures their contents, and obtains a sample mean of 11.6 ounces with a standard deviation of 0.70 ounce. Use a 0.01 significance level to test the agency's claim that the company is cheating its customers. o test statistic--4.04; critical value = -2.326;...
Problem 1) A salesman is attempting to convince a factory manager to buy a new bottle-filling...
Problem 1) A salesman is attempting to convince a factory manager to buy a new bottle-filling machine. He claims that it can dispense the fluid more accurately that the old machine, resulting in less waste. The objective is to fill bottles with at least 500 mL. but with as little extra fluid as possible. Assume a confidence level of 99%. a) The factory manager tests the new machine by filling 12 bottles. He measures the volume of each test bottle...
A local bottler in Hawaii wishes to ensure that an average of 16 ounces of passion...
A local bottler in Hawaii wishes to ensure that an average of 16 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 48 bottles. The mean weight of the passion fruit juice in thee sample is 15.80 ounces. Assume that the population standard deviation is 0.8 ounce. (You may find It useful to reference the appropriate table: z table or t table...
A local bottler in Hawaii wishes to ensure that an average of 10 ounces of passion...
A local bottler in Hawaii wishes to ensure that an average of 10 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 31 bottles. The mean weight of the passion fruit juice in the sample is 9.82 ounces. Assume that the population standard deviation is 0.51 ounce. (You may find It useful to reference the appropriate table: z table or t table)...
measured concentration of vitamin C in fruit juice. (
mol/L)
Type of juice Ppple Volume of container: 200mL Volume per serving: aob mL Servings per container: % RDA of vitamin C per serving: 1007 Calculated concentration of vitamin C based on packaging: RDA for vitamin C: 90 mg O.45 mg/mL 2.55X 10o ,mol/L Calculated molar concentration of vitamin C based on packaging: (assume molar mass is equal to that of ascorbic acid, 176.12 g/mol) Titration Data: 0.00Sm Concentration of lodine...
Q1.
Q2.
Uhom a tion of 0.305. To monitor this Question 13 (1 mark) Attempt 1 The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.4. Historically the percentage of SiO2 in the cement is normally distributed w process, periodically an engineer takes a random sample of 16 measurements. A recent sample yielded a sample mean of 5.228 Find the p-value associated with the following hypothesis test. Ho:u=5.4 versus H,: *5.4 Your answer can...
[6-34] The manufacturer of a new fiberglass tire claims that its average life will be at least 40,000 miles. To verify this claim, sample of 15 tires are tested. Sample mean was 41.1 (in 1000 miles), and sample standard deviation was 2.50. Assuming the measurements were random sample from a Normal distribution, calculate 95% one-sided confidence interval for true mean tire life. Choose lower-bound or upper-bound, whichever is appropriate. (Round to 2 decimals.) Your Answer: Answer
1) A manufacturer claims that the mean amount of juice in its 16 ounce bottles is at least 16.1 ounces. C) Two-tailed A) Right-tailed B) Left-tailed 2) A health insurer has determined that the "reasonable and customary" fee for a certain medical procedure is $1200. They suspect that the average fee charged by one particular clinic for this procedure is less than $1200 and wish to conduct a test to see if the suspicion can be supported. B) Left-tailed C)...
Please answer all 3 questions
Question 15 1 pts A local juice manufacturer distributes juice in bottles labeled 12 ounces. A government agency thinks that the company is cheating its customers. The agency selects 50 of these bottles, measures their contents, and obtains a sample mean of 11.6 ounces with a standard deviation of 0.70 ounce. Use a 0.01 significance level to test the agency's claim that the company is cheating its customers. o test statistic--4.04; critical value = -2.326;...
Problem 1) A salesman is attempting to convince a factory manager to buy a new bottle-filling machine. He claims that it can dispense the fluid more accurately that the old machine, resulting in less waste. The objective is to fill bottles with at least 500 mL. but with as little extra fluid as possible. Assume a confidence level of 99%. a) The factory manager tests the new machine by filling 12 bottles. He measures the volume of each test bottle...
A local bottler in Hawaii wishes to ensure that an average of 16 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 48 bottles. The mean weight of the passion fruit juice in thee sample is 15.80 ounces. Assume that the population standard deviation is 0.8 ounce. (You may find It useful to reference the appropriate table: z table or t table...
A local bottler in Hawaii wishes to ensure that an average of 10 ounces of passion fruit juice is used to fill each bottle. In order to analyze the accuracy of the bottling process, he takes a random sample of 31 bottles. The mean weight of the passion fruit juice in the sample is 9.82 ounces. Assume that the population standard deviation is 0.51 ounce. (You may find It useful to reference the appropriate table: z table or t table)...
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