Question

lines 14-17

C. Molar Heat of Solution NaOH 11. Temperature of water before (°C) 12. Mass of solid (s) 13. Temperature of water after (°C) 14. Heat change of solution (cal) 15. Molecular mass of solid (g/mole) Nac NHACI 19°C 18.5C 1900 1.Solog 1.500g 1.4869 182 14.8 30°C 16. Number of moles of solid 17. Molar heat of solution (kcal/ mole)

Answer 1

solute t solvent solution. yhe Energy released or abs&bed when the solute dissolves en the solvent is called Heat of solution. of molal Heat of The Energy released or absolbed per mole solute being dissolved in solvent is called solution. whe amount of Energy released or abs&bed is calculated by q=ms at so specific heat empachy AT = change in Teropetell. For Nach :- T, = 190 Te = 18°c m= 1.5069 = reallgoc m = mass q MS AT =(15069) Cicados ( 18c-6c) = -1.506 cal Nach = Molar mass म 23+35.5 - 58.591mle moles of Nad melal mass = 1.5069 58-59%md 0.0257 nol

ndal Heat of solution for Nall eq n =-11506 cand 0.0257 ml I kcal Tovo al = 10.0585 K. call mole/ Por Nitel) T = 18.5°C T2 = 14.8°C m = 1.500g Sibo = reallgoc q=ms AT = (1.509) ( 161/9C) (14.8*c-i8.5°C) q=(5.5 Cad] = 53.49Imde nolal mass gi Wited moles (2) = amu w 1.500 = 2 53.49 Inole =/0.0280 moll molal seat go schution = V/ 5.5 cal Х lk.cal lovo cal od 0-0 280 10.1964 kcal inde Per Noolts T = 19°C 22=30c ma 14869 solcellege 9 MS AT =(1-4869) cical/g"C) ( 30C-90) = 116.346 cal 40g/mole indlal mass & Noot = 1-486) n = 0.0371 amw 403 Imee -0.037/ mde

Tc m (g) molas Heat of solution for Noot =Vm = 16-3466 x lk.cal 0.37 (mole 100o mol 0.0440 Kical Inde Nall Nited NaolH 19°C isse 19°C 1.800 g 1.4869 1.5069 14.8°C T2°C 18°C 5-scal -1.506 cl Heat Change of scleten (5) molecular moss 58-59 1md 0.0257 nde Oc0280 md nem beeg 010440 kacal 0.0585k.callmde 0.1964 meal leat g' Sleethenckcal mode) 3°c 16.34666 40g (nde 53491nd 0.0377 mde meles on) kecal Imle
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