The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e− Cl(g)+e−→Cl−(g)...

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The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e− Cl(g)+e−→Cl−(g)...

The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e− Cl(g)+e−→Cl−(g) Cs+(g)+Cl−(g)→CsCl(s) Which of these steps absorb energy and which release energy?

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Answer 1

Answer #1

Cs(s)→Cs(g)

Changing from solid to gas will absorb energy

12Cl2(g)→Cl(g)

breaking bond will absorb energy

Cs(g)→Cs+(g)+e−

This is ionisation reaction. This will absorb energy

Cl(g)+e−→Cl−(g)

This will release energy.

Cs+(g)+Cl−(g)→CsCl(s)

Formation of bond releases energy

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Answer 2

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The formation of CsCl from Cs(s) and Cl2(g) involves the following steps: Cs(s)→Cs(g) 12Cl2(g)→Cl(g) Cs(g)→Cs+(g)+e− Cl(g)+e−→Cl−(g)...

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