Smartphones: A poll agency reports that 52% of teenagers aged 12-17 own smartphones. A random sample...

Question

Question

Answer 1

Answer #1

Answer:

Given,

p = 0.52

sample n = 200

standard deviation = sqrt(pq/n) = sqrt(0.52(1-0.52)/200) = 0.0353

P(X > 0.55) = P(z > (0.55 - 0.52)/0.0353)

= P(z > 0.85)

= 0.1976625 [since from z table]

= 0.1977

Answer 2

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