A 78 kg man stands on a bathroom scale at the center of an elevator. As...
A 78 kg man stands on a bathroom scale at the center of an elevator. As the elevator accelerates from rest downwards to -11.4 m/s in 3.04 s, what is the scale reading in Newtons?
Homework Answers
Vi = initial velocity = 0 m/s
Vf = final velocity = - 11.4 m/s
t = time = 3.04 sec
acceleration is given as ::
a = (Vf - Vi) / t
a = -11.4 - 0 /3.04
a = -3.75 m/s2 in downward direction
The force equation for the motion of man in the elevator is given as
mg - Fn = ma
78(9.8) - Fn = 78(3.75)
Fn = 471.9 N
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