Given a sorted (in ascending order) integer array nums of n elements and a target value, write a method to perform a binary search for a target value in nums. If target exists, then return its index, otherwise return -1. Analyze the running time, T(n).
public int search(int[] nums, int target) {
// YOUR CODE GOES HERE
} // end search
public int search(int[] nums, int target) { int low = 0; int high = nums.length - 1; int mid; while (high >= low) { mid = (low + high) / 2; if (target == nums[mid]) return mid; else if (target > nums[mid]) low = mid + 1; else high = mid - 1; } return - 1; }
Given a sorted (in ascending order) integer array nums of n elements and a target value,...
IN JAVA please Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. Your code will be tested for runtime. Code which does not output a result in logarithmic time (making roughly log(2) N comparisons) will fail the tests. A sample main function is provided so that you may test your code on sample inputs. For testing purposes, the...
Please Write in Java An array is sorted (in ascending order) if each element of the array is less than or equal to the next element . An array of size 0 or 1 is sorted Compare the first two elements of the array ; if they are out of order, the array is not sorted; otherwise, check the if the rest of the array is sorted. Write a boolean -valued method named isSorted that accepts an integer array , and the number of...
Implement a method to build an AVL tree out of a sorted (ascending order) array of unique integers, with the fastest possible big O running time. You may implement private helper methods as necessary. If your code builds a tree that is other than an AVL tree, you will not get any credit. If your code builds an AVL tree, but is not the fastest big O implementation, you will get at most 12 points. You may use any of...
using c++ Write a function that returns true if a given integer array is sorted(in ascending order) and false if it is not. The function should perform no more than "size" comparisons. bool isSorted(int A[], int size);
1. Please write a Divide-and-Conquer Java algorithm solving the following problem: Given an "almost sorted" array of distinct integers, and an integer x, return the index of x in the array. If the element x is not present in the array, return -1. "Almost sorted" means the following. Assume you had a sorted array A[0…N], and then split it into two pieces A[0…M] and A[M+1…N], and move the second piece upfront to get the following: A[M+1]…A[N]A[0]…A[M]. Thus, the "almost sorted"...
In Java: In a sorted (ascending) integer array of length n with no duplicates, print all values in the range x to y. Assume both x and y are in the array. What is the worst case big O running time if there are k integers within the range?
6.) (a) A string contains several X's followed by several O's. Devise a divide-and-conquer algorithim that finds the number of X's in the string in log2n steps, where n is the length of the string. (b) An array originally contained different numbers in ascending order but may have been subsequently rotated by a few positions. For example, the resulting array may be: 21 34 55 1 2 3 4 5 8 13 Is it possible to adapt the Binary Search...
23.1 Append to Oversize Array Java Help Given an oversize array with size1 elements and a second oversize array with size2 elements, write a method that returns the first array with the elements of the second appended to the end. If the capacity of the oversize array is not large enough to append all of the elements, append as many as will fit. Hint: Do not construct a new array. Instead, modify the contents of the oversize array inside the...
Write A JAVA mergesort method that mergesorts array elements in descending order. Write A JAVA binary search method that searches x in a sorted array with n elements and returns its position if exist, -1 otherwise.
2. (10 pts) Recall Binary Search: Input: a list of n sorted integer values and a target value Output: True if target value exists in list and location of target value, false otherwise Method: Set left to 1 and right to n Set found to false Set targetindex to - 1 While found is false and left is less than or equal to right Set mid to midpoint between left and right If target = item at mid then set...