A 10.0 kg sample of liquid water is used to cool an engine. Calculate the heat...

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A 10.0 kg sample of liquid water is used to cool an engine. Calculate the heat...

A 10.0 kg sample of liquid water is used to cool an engine. Calculate the heat removed (in joules) from the engine when the temperature of the water is raised from 293 K to 373 K. Take Cp = 75.2 J/K•mol for H2O (l)

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Answer 1

Answer #1

Heat removed from the engine = mass of water * Specific heat of water* temperature difference

since specific heat is given in J/kmol. water mass of water need to be converted to molees

moles= mass/Molecular weight

moles of water = 10 kg/18= 0.556 kg mokes

Heat removed= 0.556 kg moles* 75.2 J/kmol* (373-293)=3345 Joules

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Answer 2

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