Calculate the pH of the following solutions. Solution prepared by diluting 44.0 mL of 6.5×10−2 M...
Calculate the pH of the following solutions.
Solution prepared by diluting 44.0 mL of 6.5×10−2 M Ba(OH)2 to a volume of 323.5 mL .
Homework Answers
M1V1 = M2V2
M1 = 6.5*10^-2 M
V1 = 44.0 ml
M2 = ?
V2 = 323.5 ml
6.5*10^-2 *44 = M2*323.5
M2 = 6.5*10^-2 *44/323.5
M2 = 8.84*10^-3 M
[OH-] = M2 = 8.84*10^-3
Ph = 14 - Poh
Poh = -log[OH-]
Poh = -log[8.84*10^-3] = 2.05
Ph = 14 -2.05 = 11.95
or
Ph of Ba(OH)2 is 12
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