Homework Answers
The value of Kw at 250c is 1*10-14 .
The reaction is
CH3COOH +H2O = CH3COO- + H3O+
We know, Kw= [H+] [OH-] =1*10-14
Kw= Ka*Kb
or, Kb= Kw/Ka
or, -log Kb= - log (Kw/Ka)
or, pKb = - log ( Kw/Ka)
Or, pKb = - log (1*10-14 / Ka )kindly put Ka value from question no. 6 . You get pKb value.
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