A 197 g cube of ice at 0◦C is dropped into 1.4 kg of water that was originally at 78◦C. What is the final temperature of the water after after the ice melts? The latent heat of fusion of water is 3.33 × 105 J/kg. Answer in units of ◦C.
mass of ice = 197 g
mass of water = 1.4 kg
initial temperature is 78 C
let final temperature be T C
initial temperature of ice = 0 C
heat lost by water = heat gained by ice
MC dt=mL+mCdt'
C is specific heat of water = 1 ca;/g
L= latent heat of ice = 80 cal/g
dt=78.-T
dt'=T-0=T
1400 x 1 x (78-T)=(197 x 80) + (197 x 1 x T)
109200-1400 T=15760+197 T
T= 58.509 C
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