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You push a 3.2 kg block against a horizontal spring, compressing the spring by 27 cm....

You push a 3.2 kg block against a horizontal spring, compressing the spring by 27 cm. Then you release the block, and the spring sends it sliding across a frictionless tabletop. If the spring constant is 540 N/m, what is the speed of the block? *The answer should be 3.5 m/s, but I don't know how to get it*

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Answer #1

Spring constant K = 540 Nm compression x-27 cm 0.27 m mass of the block m - 32 Kg Let v be the speed of the block. Loss in Potential energy of spring = kinetic energy of block 540 3.2 (0.27)3507 m/s

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