VO P. 2; The switch in the circuit shown closes at t=o. . (@) First, derive...
7 ots) 4. (a) The switch in the circuit below closes at t-o. Write the differential equation governing the inductor current i(O), >0 in the circuit below. Don't solve the equation! (10 pts) 6Ω i(t) 4H t=0 20 (b) Determine the final value of the current, i(t-). (7pts)
2 First-Order RC Circuit: Natural Response The switch in the circuit in Figure 2 has been in position for a long time. At t = 0, the switch moves to position (the switch opens) and stays there. Assuming that V. > O for the constant voltage source, (a) find vc(0-), vc(0+), ic(0-), and ic(0+); (b) find vc(t) when t 20 (if you want, you can write vo(t) by circuit inspection; you don't need to show the differential equation); and (c)...
do not use s domain method ,use only differential equation 3. In the circuit shown, switch 1 has been closed for a long time before it is opened at t 0, and switch 2 has been opened for a long time before it is closed at t = 0. SW2 sw, 0.5Ω R2 1(2 A, 20 A i(t) 0.5 H a. Find the initial voltage v(O)- Vo across the capacitor and initial current through the inductor (0) lo at t...
The switch in the RC circuit shown in the diagram closes at t = 0. The emf ε = 12V, R = 10 kΩ, C = 11.88 nF. The capacitor was uncharged initially. At what time does the capacitor voltage hit 4.5 V? Express your answer up to one decimal place, and in units of microseconds. I got 55.84 microseconds as my answer...
(1) Consider the RC circuit shown in Figure 1. For t<0 the switch is open, and the charge stored on the capacitor is 0. At t-0 the switch is closed, and the voltage source begins charging the capacitor. Let R1-R2-220 Ω , C-0.47 μ F , Vs-5 V. (a) Write the differential equation as an expression for the capacitor voltage fort> 0 (i.e. write the differential equation) and calculate the time constant (b) Calculate the steady-state capacitor voltage R2 R1...
In the RC circuit shown, the capacitor is initially charged to 10 volts, and the switch closes at time t=0. The voltage across the capacitor can be described by the equation Vc(t) given below for time t>=0 (greater than, or equal to, O). Determine V_1 and V_2 for this equation. R=100KR C=o.lMF I capacitor initially I charged to 10 volts V(t) = V₂ + (VZ-V4) e ERC for tzo
The input voltage waveform (Vin) t in is shown below along with the circuit. The voltage-controlled switch S1 closes when the output voltage Vc (t) goes positive at t=0 and opens when Vc (t) goes negative at t=5 µs. Assume that Vin(t) in has been at 10 V for t<0 for a very long time.. 3. (15 marks) The input voltage waveform Vin(t) is shown below along with the circuit. The voltage- controlled switch S, closes when the output voltage...
For the circuit shown, find the following: a) v(0+), the voltage across the capacitor right after the switch closes. b) v), the voltage across the capacitor after the switch has been closed for a long time. c) v(T), the voltage across the capacitor after one time constant. 2. 3 S2 I(t) 12 V+ 6 Ω 0.5 F u(t) 3. For the circuit above, write the differential equation for t > 0.
The R1 value is 2k 3. [15p] Assume that the switch in the circuit shown below has been in the position a for a long enough time, and then thrown to the position b, at t=0. R=0b R2-4k92 (a) [lp] Fort > 0, find the initial capacitor voltage at t = 0+sec, v.(0+). + OR + Vio V=100 ( voc=luf Ç v=51 I (b) [2p] For t > 0, find the final capacitor voltage at t → o sec, v..)....
For the circuit shown, the switch has been open for a long time and it closes a t=0. The initial energy stored in capacitor is 250 . 102 w 3V 05v, 522 1c 20 F Question 6: What is the initial condition of the voltage of the capacitor? (A) 0 V (C) 1V (E) None of the above (B) 5 V (D) 3V (E) Question 7: What is the value of v, at t=0*? (A) -3V (C) 2V (E) None...