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a lon sans faire des Mon blog de monti di 3. Let f(0) = S 1; XEQ Then using the sequential definition of limit, prove that li
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Answer #1

f(1) f!; XE CC limewaq. 0; ze slim f(x) = ? . We know that, o and ge both ane dense in IR. 1st. we considen a sequence of natBut . 98 (81)} to limit if exits then it must be unique . Hence, {fland 3 n 1 and {flon}nto. which is a contradiction Hence,

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