Question

Python 3.6 (known limitations) 1 mashup=(2, 'abc', 1, 'def'] 2 x=mashup[1][0] 3 print(x) Edit this code xecuted

can some one help me explain this please? I dont understand it

Answer 1

mashup = [2,'abc',1,'def']

mashup is a list that contains 2 , 'abc', 1, 'def'

List index is stating from 0

So,

mashup[0] = 2
mashup[0] = 'abc'
mashup[0] = 1
mashup[0] = 'def'

You can see in below picture. I have printed mashup[0],mashup[1],mashup[2],mashup[3]

main.py 1 2 mashup = [2, 'abc',1, 'def'] 3 4 print(mashup[@]) 5 print(mashup[1]) 6 print(mashup[2]) 7 print(mashup[:]) 8 9 2 abc 1 def ... Program finished with exit code o Press ENTER to exit console. I

Now mashup[1] = 'abc'. abc is a string.

To access each character of string
mashup[1][0] = 'a'
mashup[1][1] = 'b'
mashup[1][2] = 'c'

You can see the below picture.

main.py 1 2 mashup = [2, 'abc',1, 'def'] 3 4 print(mashup[1][@]) 5 print(mashup[1][1]) 6 print(mashup[1][2]) 7 8 a с Program finished with exit code o Press ENTER to exit console. I

x = mashup[1][0]

Above statement will assign the value of mashup[1][0] to x

So value of x becomes value of mashup[1][0] that is 'a'

So value of x becomes a.

and then print(x) will print the value of x. that is 'a'. So output is a

main.py 1 2 mashup = [2, 'abc',1, 'def'] x = mashup[1][@] 4 print(x) 5 3 6 a ...Program finished with exit code o Press ENTER to exit console.