Question

a rod is radioactive and its length must be measured from a distance. light with a wavelength of 512 nm falls on a single slit 0.247 mm wide. the diffeaction pattern is projected onto the rod, using the rod as a screen. the rod is 2.50 m from the slit. the m =-3 dark fringe falls on one end if the rod and the m = 18 dark fringe falls on the other end. what is the length of the rod?

QUESTION 1 A rod is radioactive and its length must be measured from a distance. Light with a wavelength of 512 nm falls on a single slit 0.247 mm wide. The diffraction pattern is projected onto the rod, using the rod as a screen. The rod is 2.50 m from the slit. The m-3 dark fringe falls on one end of the rod and the m - 18 dark fringe falls on the other end. What is the length of the rod? 9.59 x 10-2 m Ο Α. ОВ. 0.109 m Ос. 1.28 m OD. 0.114 m OE. 7.77 x 102 m

Answer 1

m=3 li d 03 vo D 18 m=18 FB minima, the conditim t ma = is d sino for m3, -3 247x10 Sings = 3x512x10 o > Og = 0.356 D tan O3 li= li= 2050x tam (0.356) l = 0.0155m -9 for m=18 -3 0.24 7 X 10 sinops = (8x512x10 Pia = 2:14 e, D tano, 18 la = 2.50 tan 2.14 l 0.0934 m = length of rod litla e = l oo10am optim-B