Question

Powers of numbers can be calculated by multiplying the number by itself for as many times as the value of the exponent. For example, 2 raised to the power 4 can be calculated by multiplying 2 by itself 4 times to get 16. Write a program that:

1. inputs a double as the base number and an int as the exponent;
2. multiplies the base number by itself using a loop that repeats for the

number of times in the int;
3. outputs the exponential value calculated.

Use an if statement for the special case where the output is 1 if the int value is 0. For a more challenging version, deal with the case where the exponent is negative.

Programm language c++

Answer 1

#include <iostream>

using namespace std;

int exponentPower(int a, int b){

int result = 1;

if(b==0)

return 1;

for(int i=1;i<=b; ++i)

result = result*a;

return result;

}

int main() {

cout<< exponentPower(2,3)<<endl;

cout<< exponentPower(2,4)<<endl;

}

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SEE OUTPUT

Files : main.cpp 6 D saving... 1 #include <iostream> 2 using namespace std; 3 int exponentPower(int a, int b) { clang version 7.0.0-3~ubuntu0.1 > clang++-7-pthread -o main ma > ./main main.cpp nmn 16 int result = 1; if(b==0) return 1; for(int i=1;i<=b; ++i) result = result*a; 0 0 10 11 return result; 12 13 14 15 16 int main() { cout<< exponentPower(2,3)<<endl; cout<< exponentPower(2,4)<<endl; } 17 18

Thanks, PLEASE COMMENT if there is any concern.

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