Question

nich (6 pts) atom in the molecule shown will be most readily abstracted by a bromine radical? Hd Hb H HcH He A) Ha B) Hb С) Н
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Answer #1

que 2.  Hc will get abtracted.

because radical formed will be in conjugation with double bond and resonate.

thus is resonance stablised.

so c is the right option.

leren - A | | - H . Muut 1

que 3.

step1 Initiation step-Formation of radical by homolytic cleavage of Cl2 bond.

step2 propagation step- radical will abstract H and form C radical.

step.3 termination step- fromation of final product.

thu Chce ਉਸ ਨੂੰ + 4Hope it helps you, pls thumbs up.

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