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yi 24 The joint probability function of Y1 and Y2 is given. 0 1/8 3/8 Y2 1 2/8 1/8 3 0 1/8 Find (a) Cov(Y1, Y2) and (b) the c

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Answer #1
y1
y2 2 4 Total
0    1/8    3/8    1/2
1    1/4    1/8    3/8
3 0           1/8    1/8
Total    3/8    5/8 1       

marginal distribution of Y1:

y1 P(y1) y1P(y1) y1^2P(y1)
2    3/8 0.7500 1.5000
4    5/8 2.5000 10.0000
total 1.0000 3.2500 11.5000
E(y1) = 3.2500
E(y1^2) = 11.5000
Var(y1)=σy= E(y1^2)-(E(y1))^2 0.9375

marginal distribution of Y2:

y2 P(y2) y2P(y2) y2^2P(y2)
0    1/2 0.0000 0.0000
1    3/8 0.3750 0.3750
3    1/8 0.3750 1.1250
total 1 0.75 1.5
E(y2) = 0.7500
E(y2^2) = 1.5000
Var(y2)= E(y2^2)-(E(y2))^2 0.9375

E(y1*Y2) =0*2*1/8+0*4*3/8+1*2*2/8+1*4*1/8+3*2*0+3*4*1/8=2.500

a)

Covar(y1,y2)=E(y1y2)-E(Y1)*E(y2)= 1/16 = 0.0625

b)

Correlation coefficient =Cov(y1,y2)/√(σy1*σy2)= 1/15 = 0.0667
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