Question

Please work problem 2-5.

2.3 VECTOR ADDITION OF FORCES *2-4. The vertical force Facts downward at A on the two- membered frame. Determine the magnitudes of the two components of F directed along the axes of AB and AC. Set F = 500 N. 2-5. Solve Prob. 2-4 with F = 350 lb. Probs. 2-415

Answer 1

2-4 ) .

As we can clearly see from the figure that the force F makes an angle 60⁰ with axis of AC.

Therefore, component of F along AC will be
F cos 60"
and component of F along AB will be
F sin 600
.

Component of force along AC =

F cos 60"

= 500 *

   N

= 250

Component of force along AB =

F sin 600

= 500 * 3

= 250V3

= 433.01 N

2-5 ) .

Component of force along AC =

F cos 60"

  

= 350 *

   lb

= 175

Component of force along AB =

F sin 600

  

= 350 + V

  

= 175V3

lb

= 303.1