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Find the area of the surface generated by revolving x=t+w - 2 sts V2 about the y-axis. The surface area obtained by revolving
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Frida کد - 2 + کی 2 face of the surface gerected by revolving x = + +52 ) y = +2 + So t . about the y-axis is given by: للغارLet +24 24 52 + 3 = v = 2t + 252 t: -52 to 52 v = 2 & 452) vill to a) du= 2(+ +52)dt ( dv Sv A = z[CVJETA ^-[** ] Azst) A =>

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