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JU 2. [5 points) If w = 63+4(.22 + 3j2) and x = (r – s) and y = (r +s)?, then the value of when r=1 and s=0 is (A) 244 (B) 18

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Answer #1

Here we use the chain rule to find the partial derivative and get the result.ven 8 o even w = e 3x+y (x² + y2) x= (r-8)2 y = (r+s)? - Here we use chain rule to - (2) find the partial derivatives. OX 2 1= *e***(0+1) + [[72] (esetz) (osz (3+)) tezuty (24) ] - ates*** + [ gode 3*** (0+1) + 24e3***] 2 SX+ 2 3xty 3nty ne = **** (xWhen r=1, 8=0, 2 | 3( +(1+0)? = (3(1-0)*+ 3 (1+0)*+2(1–0) Jrol,b=0 +2[ 310-*000$ (10)26005-2005) (1+0)7 et (3+3+2) (1)] +2[é

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