Question

A Proton between Oppositely Charged Plates A uniform electric field exists in the region between two oppositely charged parallel plates 1.55 cm apart. A proton is released from rest at the surface of the positively charged plate and strikes the surface of the opposite plate in a time interval 1.56x10-6 s.

Answer 1

A)

Force, F = qE = ma

Acceleration, a = qE/m

Using 2nd equation of motion,

s = 0.5 at^2

s = 0.5 (qE/m) t^2

E = 2 sm/qt^2

E = (2 x 0.0155 x 1.67 x 10^-27)/(1.6 x 10^-19 x (1.56 x 10^-6)^2)

E = 132.96 N/C

B)

Velocity, v = at = (qE/m) t

v = (1.6 x 10^-19 x 132.96/1.67 x 10^-27) x 1.56 x 10^-6

v = 1.98 x 10^4 m/s

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