Can anyone please help me to simplify the two Z1 and Z2 expressions using boolean identities? then help me to draw the logisgm circuit.
(POS) Boolean algebra Z1 = (X1∙X2∙~X3∙X4) ∙ (X1∙~X2∙X3∙~X4) ∙ (~X1∙X2∙X3∙X4) ∙ (~X1∙X2∙3∙X4) ∙ (~X1∙~X2∙~X3∙X4) ∙ (~X1∙~X2∙~X3∙~X4)
Kmap simplify algebra: Z1 = (X2.~X3.X4)+(~X1.X2.X4)+(~X1.~X2.~X3)+(X1.~X2.X3.~X4)
(POS) Boolean algebra Z2 = (X1∙X2∙X3∙X4) ∙ (X1∙X2∙X3∙~X4) ∙ (X1∙~X2∙X3∙~X4) ∙ (X1∙~X2∙~X3∙~X4) ∙ (~X1∙X2∙X3∙~X4) ∙ (~X1∙X2∙~X3∙~X4) ∙ (~X1∙~X2∙X3∙~X4)
Kmap simplify algebra: Z1 = (X3.~X4)+(X1.X2.X3)+(X1.~X2.~X4)+(~X1.X2.~X4)
please help me to simplify these two;
Z1 = (X2.~X3.X4)+(~X1.X2.X4)+(~X1.~X2.~X3)+(X1.~X2.X3.~X4)
Z1 = (X3.~X4)+(X1.X2.X3)+(X1.~X2.~X4)+(~X1.X2.~X4)
Can anyone please help me to simplify the two Z1 and Z2 expressions using boolean identities?...
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