A friend of yours doing research brags that she has measured 10.00 picograms of Iron (II)...

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Answer 1

Answer #1

Given that, 10 .00 picograms is iron (II) phosphate ; Fe₃O₈P₂

1 .00 pg = 1e-12 g

10 .00 picograms *1*10^-12 g/ 1.00 picograms = 1.0*10^-11 g

Number of moles in 10 .00 picograms or 1.0*10^-11 g

= amount in g/ molar mass

= 1.0*10^-11 g Fe₃O₈P₂/ molar mass

= 1.0*10^-11 g/ 357.48 g/ mole

= 2.80*10^-14 moles

Now convert mole into molecules

= 2.80*10^-14 moles * 6.23*10^23 molecule / 1 mole

= 1.68*10^10 molecules

1 molecule of Fe₃O₈P₂ contains = 8 atom O

1.68*10^10 molecules will contain

= 1.68*10^10 molecules *8 atom O /1 molecule of Fe₃O₈P₂

= 1.344*10^11 atoms O

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Answer 2

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