2. An object on the moon falls with a constant gravitational acceleration of −1.6m/s2. An astronaut drops a hammer from a height of 6m with an initial velocity of 0m/s.
(a) Find the position function s(t) and the velocity function v(t) of the hammer.
(b) After how many seconds will the hammer hit the ground?
**Can you give me the solution step by step by using notes or videos? So I can understand
2. An object on the moon falls with a constant gravitational acceleration of −1.6m/s2. An astronaut...
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 50 ft per sec. The height s of the ball in feet is given by the equation s=-2.7 t²+50 t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b.a. After how many seconds is the ball 14 ft above the moon's surface?After _______ seconds the ball will...
Suppose an object falls from a great height on a planet where the acceleration constant of gravity is g = 7.29. Suppose that the resistance of the atmosphere is proportional to the square of the speed of the object with constant of proportionality k = 0.36. Establish and solve an Initial Value Problem to express the velocity of the object as a function of time. Find the terminal velocity of the object. Graph this function. Then express the fallen distance...
6) An object is originally moving and a constant acceleration of 8 m/s2 is applied to it +x direction which causes it stop after 2.0 seconds. What was the magnitude of the initial velocity in m/s?
9) Assume that a moving object has constant acceleration a for all t>0 a) Determine a function, v(t), for the velocity of the object. i. For you function, what is v(0)? ii. Is your v(t) the only possible function or are there other possibilities? iii. Describe all possible v(t) b) Determine a function s(t) for the position of the object. What is s(0)? i. ii. Describe all possible s(t) We know that acceleration due to gravity on earth is about...
An object moves in one dimensional motion with constant acceleration a = 6.9 m/s2. At time t = 0 s, the object is at x0 = 1.7 m and has an initial velocity of v0 = 3.6 m/s. How far will the object move before it achieves a velocity of v = 6.2 m/s? Your answer should be accurate to the nearest 0.1 m.
An object moves in one dimensional motion with constant acceleration a = 5.9 m/s2. At time t = 0 s, the object is at x0 = 4.1 m and has an initial velocity of v0 = 4.4 m/s. How far will the object move before it achieves a velocity of v = 8.5 m/s? Your answer should be accurate to the nearest 0.1 m.
An object moves in one dimensional motion with constant acceleration a = 4.8 m/s2. At time t = 0 s, the object is at x0 = 1.4 m and has an initial velocity of v0 = 3.6 m/s. How far will the object move before it achieves a velocity of v = 6.5 m/s? Your answer should be accurate to the nearest 0.1 m.
An object moves in one dimensional motion with constant acceleration a = 3.2 m/s2. At time t = 0 s, the object is at x0 = 2.2 m and has an initial velocity of v0 = 4.9 m/s. How far will the object move before it achieves a velocity of v = 8.4 m/s? Your answer should be accurate to the nearest 0.1 m.
Can you please give me the whole solution for this question! Thanks 2. According to Newton's Law of Universal Gravitation, the gravitational force on an object of mass m that has been projected vertically upward from Earth's surface is F( is the objer s distan boe he urfac at time t, Ris Earth's radius, ngR (x+R)2 and g is the acceleration due to gravity. Also, by Newton's Second law, mgR2 (x +R)2 dv F = mal = m dt =...
Problem 1. A car with constant acceleration of 2.3 m/s2 drives toward east (positive x-axces). (a)How much time in seconds is required for the car to change its speed from 10 m/s to 35 m/s? (b)Calculate the total distance in meters, covered during that time (c) Calculate the average speed during that time interval (d) Find x- and y- components of the vector of acceleration Problem2. From the top of a tower, a person drops a pebble. The peble strikes...