Please generate a truth table and answer "Is the compound statement a tautology?"
(p ↔ q) ↔ [ (q → p) ∨ (p → ~ q) ]
p | q |
(p ↔ q) ↔ [ (q → p) ∨ (p → ~ q) ] |
---|---|---|
F | F | T |
F | T | F |
T | F | F |
T | T | T |
From the above truth table we can say that
(p ↔ q) ↔ [ (q → p) ∨ (p → ~ q) ] is not a tautology
Please generate a truth table and answer "Is the compound statement a tautology?" (p ↔ q)...
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