Question

3.10m olo Outside diameter (od: 0.0308102 Geometric mean Radissim:0.01225296m Question ; 2-) Calculate the Land the c parameters of the transmission line. 2 - Find RLC Parameters of the transmission line for one meter length. Consider that the transmission line is transposed. 3- Model 240 km of that line using Nominal-T circuit. Write the values of impedances and admittances in the circuit.

R=0.054

Answer 1

056mour » 4.15m 4.15 m 0 0 5.18m 2 3'lm. c 5'18m de 00308102 radius => cm. ög 00154051m, в в g'=60154051x0°1788) m O'56m = 00119975m. Pa's - DcB! =(415-0'28)2 +(3012 4 95852m. Dad' = Depo =/ 4915+028)2 +(3^U2 = 5140693m, So, Geometric mean distance GMD = (PABODAB. DAC DAC DAB DAB DAC DAC DBA.DBA .DBC OP DBC OB'A PB'A . Do'c DB C DCA IDEA. DEB. DCB: DCA IDEA Depo Dd'B') /24 > GMD = 6'058354 m, Geometric mean radius → GMR = (DAA PAA. DAA' DA'A DBB .DBB'. PBB. PBB' . Dec Ocel De'c Dec) = (506. (056)6) 12 GMR = 0.081967 m.

13 So, L = 2x10-7 in GMD GMR ) = 8.6058 X10-7H/m, considering, tro1] line to neutral, 2HEO C- -= 1*29289 x10 " Flm, In /GMDI considering, Ex=1] GMR 27 50, L= 0-86058 mm/km, C = 0.0129 289 uf/km. As, R = 0.054/m, For 1 metre length R:0°054 2 L= 0'86058 un. C = 0.0129289 nf.

for 240 km line R: (0-054 x 240 x1000) = 12.96 kb. L = 2065392 MH. e= 3-102936 uf. For 50Hz line, Z=ģCUL = 280*50 x 206*5392x10-32 = 648862 - Auc = 5 20 50 x 3'lO2936x torº U - O9748 m * % = 0'4874 mo So, a network → 1296ke 9648862 mm V = 10-4874 m2 j 094874