Question

Please help with the blank starred problems!! if more info needs to be given, please tell me what else you'd need because I don't know.

VOOL Data report sheet. Name Desk # Room # Box 3. Weak base: data and calculations Measurements (a) Volume of weak base stock solution diluted 11.60mL 700 (b) Concentration of weak base stock solution = 0.100M (c) Concentration of weak base after dilution - find (d) Weak base measured pH : trial I - 10:41 trial 2 -10.76 , average - 10.795 Calculations to determine Ks of the base (e) Weak base, pOH (calculated using (d), the average measured pH) = (1) Weak base, [OH) - (g) Weak base, ks (from equation VT) = Box 4. Salt of weak base: data and calculations Measurements (a) Mass of salt (b) Concentration of the salt solution = (c) Measured pH of salt solution: trial 1 - 5-74. trial 2 Calculations to predict the pH of the salt 0.489 0.01M average - 5.745 (d) Ks of the weak base (from box 310) = (e) K of the salt solution (from equation (9)) = (Predicted [H] of salt solution (from equation (13)) (g) Predicted pH of salt solution = = Box 5. Salt of unknown: data and calculations (a) Concentration of the salt solution = 6) Measured pli of salt solution: trial 1 - 3.1 Calculations to predict the pH of the salt . trial 2 = 3.09. average - 3.05 (c) K, of the weak base (if appropriate)= d) Ks of the parent weak acid (if appropriate) = 96

Answer 1

The concentration of the weak base after dilution = 11 mL * 0.1 M/100 mL = 0.011 M

Weak base measured pOH = 14 - pOH = 14 - 10.795 = 3.205

Weak base [OH^-] = 10^-pOH = 10^-3.205 = 6.237*10^-4 M

Weak base Kb = [OH^-]²/(concentration of the weak base after dilution - [OH^-]) = (10^-3.205)²/(0.011 - 10^-3.205) = 3.749*10^-5