Question

a generic salt AB2, has a molar mass of 323 g/mol and a solubility of 8.80...

a generic salt AB2, has a molar mass of 323 g/mol and a solubility of 8.80 g/l at 25 degrees celcius. what is the ksp of this salt at 25 degrees.

AB2(s)>>>>>A2+(aq)+2B-(aq)

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Answer #1
Concepts and reason

Calculate the solubility of each ion from the given concentration of the salt. Solubility product is the product of the individual ion concentrations.

Fundamentals

The solubility product of a salt is a measure of the solubility of a salt in water at a given temperature. The solubility product is the equilibrium constant for a salt that is partially soluble in water such that an equilibrium exists between the solid salt and the dissociated ions.

A salt dissociates in water as follows:

A,B,
XA + yB**

The solubility product for this salt is given as follows:

Ky=[A l[B*]

Here, is the solubility product, and [A
] and [B**]
is the solubility of the ions, in mol
, raised to the power of the coefficient of the ions.

Note that has no units, because the quantities used in the expression for equilibrium constants are activities of the ions, and for a dilute solution activity of the ion is equal to the concentration of the ions.

The given salt is which dissociates in water as follows:

AB,
A?- +2B*

The solubility of the given salt is 2.724x102 mol l
.

The given salt is which dissociates in water as follows:

The solubility product for this salt is given as follows:

K.-=[A? ][B]
=(s)(25)
= 453

Substitute s as 2.724x102
and calculate as follows:

K = 45
= 4(2.724x102)
= 8.085x10-5
8.09x10-5

The solubility product for this salt is 8.09x10-1
.

Ans:

The for the given salt at is 8.09x10-1
.

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