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Above what Fe2+ concentration will Fe(OH)2 precipitate from a buffer solution that has a pH of...

Above what Fe2+ concentration will Fe(OH)2 precipitate from a buffer solution that has a pH of 9.99? The Ksp of Fe(OH)2 is 4.87
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Answer #1
Concept and reason

The concept used is to calculate the concentration of .

Fundamentals

The solubility product, is the equilibrium constant for a solid that is dissolved in a solution. It is the product of the concentration of the products raised to the power of their coefficients.

is the measure of hydrogen ion concentration. Lower the , higher is the hydrogen ion concentration and lower is the hydroxide ion concentration.

Higher the , lower is the hydrogen ion concentration and higher is the hydroxide ion concentration.

The hydrogen ion concentration is calculated as follows:

[H]=10-PH1

The hydroxide ion concentration and are related as follows:

[H+ ][OH-]=1.0x10-4

1.

pH = 9.99

The hydrogen ion concentration is as follows:

[H+]=10 PH
= 10-999
= 1.023x10-10 M

The hydroxide ion concentration is as follows:

(1.023x10-)[OH-] = 1.0x10-16
Toh )- 1.0x10-14
[OH]=1.02x10-10
= 9.78x10-M

The given salt is Fe(OH)2
.

Its dissociation in water is as follows:

Fe(OH)2 (aq)>Fe* +20H

The expression for the solubility product is as follows:

[-10] -20.] = y

Substitute the values of solubility product and the hydroxide ion concentration in the formula for solubility product and calculate the concentration of as follows:

4.87x10- =[Fe2+ ](9.78x10-)!
[Fe2+] = 4.87x10-
[Fe
(9.78x10-5)
= 5.1x10-M

Ans: Part 1

Therefore, the / Fe2
is 5.1x10M
.

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