Question

4. (8 points) A random sample of 18 cigarettes of a certain brand gave a variance of 0.06 in the nicotine content per cigarette in the sample Find a 99% confidence interval for the variance of the nicotine content in all cigarettes of this brand, assuming that the nicotine content is n distributed. ormally ges missing. If we take a r
0 0
Add a comment Improve this question Transcribed image text
Answer #1

qchisq(0.005,17)
[1] 5.697217
> qchisq(1-0.005,17)
[1] 35.71847(n-) s2 2 2 2. 2 So CI is は 0.06 35 . 05 61 1 02 35 1 I 0 2 35.5 ニ (0.028) 9)

Add a comment
Know the answer?
Add Answer to:
4. (8 points) A random sample of 18 cigarettes of a certain brand gave a variance...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 3. The nicotine content in cigarettes of a certain brand is normally distributed with mean (in...

    3. The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) 4. The brand advertises that the mean nicotine content of their cigarettes is 1.5, but measurements on a random sample of 100 cigarettes of this brand gave a mean of r = 1.53 and standard deviation s=0.1. Is there sufficient evidence in the sample to suggest that the mean nicotine content is actually higher than advertised? Use a = 0.05. (Hint: follow the...

  • (1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean...

    (1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) μ and standard deviation σ=0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a random sample of 15 cigarettes of this brand. The sample yields an average of 1.4 mg of nicotine. Conduct a test...

  • Question 8 1 pts To help consumers assess the risks they are taking the Food and...

    Question 8 1 pts To help consumers assess the risks they are taking the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette gave a mean nicotine content of 28.5 milligrams and standard deviation of 2.8 milligrams for a sample of n = 9 cigarettes. The FDA claims that the mean nicotine content exceeds 31.7 milligrams for this brand...

  • Question 8 1 pts To help consumers assess the risks they are taking, the Food and...

    Question 8 1 pts To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette gave a mean nicotine content of 28.5 milligrams and standard deviation of 2.8 milligrams for a sample of n = 9 cigarettes. The FDA claims that the mean nicotine content exceeds 31.7 milligrams for this brand...

  • (1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean...

    (1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) u and standard deviation o= 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a SRS of 20 cigarettes of this brand. The sample yields an average of 1.55 mg of nicotine. Conduct a test...

  • (1 point) The nicotine content in a single cigarette of a particular brand is a random...

    (1 point) The nicotine content in a single cigarette of a particular brand is a random variable having a probability distribution with a mean of 4.4 milligrams (mgs) and a standard deviation of 0.15 mg. n = 60 of these cigarettes are chosen at random and the nicotine content of each cigarette is measured. What is the probability that the mean nicotine content of this sample is between 4.38 mgs to 4.46 mgs?

  • (1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean...

    (1 point) The nicotine content in cigarettes of a certain brand is normally distributed with mean (in milligrams) u and standard deviation o= 0.1. The brand advertises that the mean nicotine content of their cigarettes is 1.5 mg. Now, suppose a reporter wants to test whether the mean nicotine content is actually higher than advertised. He takes measurements from a SRS of 20 cigarettes of this brand. The sample yields an average of 1.4 mg of nicotine. Conduct a test...

  • To help consumers assess the risks they are taking, the Food and Drug administration publishes the...

    To help consumers assess the risks they are taking, the Food and Drug administration publishes the amount of nicotine found in all commerical brands of cigs. A new cig has recently been marketed. The FDA tests on this cigarette gave a mean nicotine content of 28.4 milligrams and standard deviation of 2.6 milligrams for a sample of n =9 cigarettes. Assume the amounts of nicotine are normally distributed. A) construct a 90% confidence interval that estimates the mean nicotine content...

  • Question 8 4 pts Ti At 1 To help consumers assess the risks they are taking,...

    Question 8 4 pts Ti At 1 To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nicotine found in all commercial brands of cigarettes. A new cigarette has recently been marketed. The FDA tests on this cigarette yielded mean nicotine content of 26.4 milligrams and standard deviation of 2.9 milligrams for a sample of n=16 cigarettes. The 988 confidence interval for the mean nicotine content of this brand of cigarette...

  • 2. Let u be the mileage of a certain brand of tire. A sample of n = 20 tires is taken at random, resulting in the sampl...

    2. Let u be the mileage of a certain brand of tire. A sample of n = 20 tires is taken at random, resulting in the sample mean X = 32, 215 and sample variance s2 = 3, 116. Assuming that the distribution is normal, find a 99 percent confidence interval for u.

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT