answer)
To find the standard deviation we will first consider the mid point
2 with frequency 5
6 with frequency 5
10 with frequency 30
14 with 10
18 with 10
First we need to estimate the mean
Mean = (sum of midpoint*frequency)/(sum of frequencies)
Mean = (2*5 + 6*5 + 10*30 + 14*10 + 18*10)/(5+5...)
Mean = 11
Now we need to subtract mean from each and every observations and take the square
(2-11)^2, (6-11)^1...
Now we need to multiply them with their respective frequencies and add them
(2-11)^2*5 + (6-11)^2*5....
= 1140
Now we need to divide 1140 by n-1 (sum of frequencies - 1) and take the square root
S.d = 4.396
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A recent study at a local college claimed that the proportion, p, of students who commute more than fifteen miles to school is no more than 15%. If a random sample of 275 students at this college is selected, and it is found that 55 commute more than fifteen miles to school, can we reject the college's claim at the 0.1 level of significance? Perform a one-tailed test. Then fill in the table below Carry your intermediate computations to at...
A recent study at a local college claimed that the proportion, p, of students who commute more than fifteen miles to school is no more than 25%. If a random sample of 275 students at this college is selected, and it is found that 87 commute more than fifteen miles to school, can we reject the college's claim at the 0.05 level of significance? Perform a one-tailed test. Then fill in the table below Carry your intermediate computations to at...
A recent study at a local college claimed that the proportion, p. of students who commute more than fifteen miles to school is no more than 15%. If a random sample of 255 students at this college is selected, and it is found that 53 commute more than fifteen miles to school, can we reject the college's claim at the 0.01 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at...
A recent study at a local college claimed that the proportion, p, of students who commute more than fifteen miles to school is no more than 25%. If a random sample of 255 students at this college is selected, and it is found that 70 commute more than fifteen miles to school, can we reject the college's claim at the 0.01 level of significance? Perform a one-tailed test. Then fill in the table below. Carry your intermediate computations to at...