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Assuming complete dissociation, what is the pH of a 4.01 mg/L Ba(OH)2 solution?

Assuming complete dissociation, what is the pH of a 4.01 mg/L Ba(OH)2 solution?
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Concepts and reason

stands for negative logarithm of concentration of hydrogen ion. The value increases with the decreasing concentration of hydrogen ion or with an increasing concentration of hydroxide ionГон]
.

Fundamentals

Arrhenius Acid-Base Theory:

Acid:

It is a chemical substance which donates protons (hydrogen ion, ) when dissolved in water.

For example,

HCl(aq) +H2O(1)–
>H,0+ (aq) + Cl (aq)

Base:

It is a chemical substance which donates hydroxyl ion, when dissolved in water.

For example,

NaOH(aq) +H2O(1) —
Nat (aq) +OH(aq)

Concentration:

Molar concentration of a solution is defined as the number of moles of solute dissolved in one liter of solution. It is expressed as mol/L or M.

Dissociation constant of water: (ion product constant)

Kw = [H+ ][CH]
[HTOH)=1.0~10:4
K. = 1.0*10**

171.34 g
Molar mass of Ba(OH)2 =
1 mol
Conversion :
4.01 mg 10-g, Imol _ 2.34x10 mol
IL Img 171.34gL

Ba(OH), (aq) +H,001) —→Ba2+ (aq) + 20H (aq)
Ba(OH),:OH* =1:2
So,[OH ] = 2x2.34x10^mol L
Using, [H][OH]=1.0x10

1.0x10-14
[]* 2x2.34x10-5
[*]= 2.137x10-1 mol L
pH = -log[H*]
pH = -log(2.137x10-10)

pH = 9.67

Ans:

The pH of a 4.01 mg/L Ba(OH)
solution is 9.67.

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