Question

How the second page comes from. Can you explain the hole page for me? I do not understand all the hole page.
12:01 Sat 25 Apr 94% Dynamics s ē t * ... Dynamics Engineering Mechanics_Dynamics (PDF Drive.com) 0 = 4 rad/sec y Sample 5/16 (British Units) The motion of slider A is separately controlled, and at this instant, p= 6 in., r =5 in./sec, and ri =81 in./sec. Determine the absolute velocity and acceleration of A for this position. VA =@xp+p = 10 rad/sec2 Va=4kx6i+5i = 24j +5i in./sec A=/(24)+(5)2 = 24.5 in./sec ag=0x(@xp) +ox p+2oxp+P ox(@xp) = 4k (4k 6i) = 4k x 24j=-961 in./sec? oxp=-10kx6i =-60j in./sec? sp_05_16_01 20x p=2(4k)*5i =40j in./sec2 P =8li in./sec a, =(81–96)i +(40–60)j=-15 – 20j in./sec? an=J45) +(20)2 = 25 in./sec? Engineering Mechanics Dynamics -- IA
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Answer 1

w = 4 radlec DVár turad/ ation of part a are calculated (that is of the body itself )(x4) ris taken as e r = 16 in s=5 inlec 8=81 in se (displacement) (speed) Cacceleration) sit & disc is So motion of the the of it & as combination Tw=4k we to h it (like our motion on our. in first page displacement , velocity &acceleration of part. g about the axes given in the problem (that is of the body VA = 80tr A is sliding along xaxis VA - C X61 15 so risi8 are along xaxis only = 249 +57 = √( 243 4 5 so 8=6i in TVA = 24.5 in/sec. I 8=s i in/sec about frame (R-Y) 1 * = es insect A = x ' rw + red + 2 w x 8 of 2 (radiod kortion) (tangential) (corolli}) (line (radial) you = (texColx 4h) = 4RX 249 = -961 inseera (tangential riw - - 10kx6l = -60) in /sec? (corolli's) 20% = 2 (4W) x 5i = 409 insseer i = 8h in/sec OA = (81-96)i + (40 -60)] = -151-20 -V (15)+ (20) = | 25 in/sec2-9 about from (ay) at na ~96 i inleef disc rotating about 2-aars osque (cow) W = -10h (ow) these are of the disc

18 AY related frome & In page 2' displacement, speed & acceleration of the slider A are calculated with respect to global frame (x-7) TR, R Ř Ira=gr Corp is similar to r). Po (x+y) L = 6 Coso )* +(sino j) (new frame no need to I = root of take them +fx(cose it sinoj) to coso î+ 5sinoj) do Ž s is also divided into components in the frame L X-y same as r SA SA= ( 34 coso I o da sino ? ) + (5 caso it 5 sino?) Lora all are zero Close is being

(-84 sino toy cosoi + (24.coso-+5 sºno s I r = = -24 Sino 45 coso 15 24 cosot 5 sino than A = wx(wx + (xv)+ (2xwxfo) + Ý = 4kx ( Gâx (6coso i +65inoſ ))+ Gokx (Gcaso î 46 snoj )) +(2x 4 x (56ogoî+5 sin oſ))+(81 Coso 1 4 01 Sinoj) ? components of sin Xoy frame ) MAF té aq asoj-a4 sine i ) + (-60 coso j + Go sinon )+ (2x (20 6050 ) +(21 coso î+ 86 6103j a 2osinoill 4k zqcoso , ĵt l-Go coso cose t o Bicoso 17 she +40sino i î go coso ) j 181 Sino / (-965BAO ? -96 coso ) (Go sino & do sino ) i (81 caso se cose To F | 408050 ) + ( ei sino a O COSO Page 1 & page a both are same way of getting For A al CAVA & MA (A) only the difference is page 1 is about AINA local frame (x-4); page 2 is about general frame (x ) In page of VALOA are given in the form of components (x-7) In page 1 no component division because TAITAVA along a-only (slider A).
Please look about the information written in boxes they will get you to easy understanding. Information written at the end is also important to understand the solution. Nothing panic page1 and page 2 both are similar only the reference axes changed. Any doubt please text me.