Question

int. What is the distance between a line that contains points A(11, -1) and B(-3, -11) and Point P(-1,1)

these are the steps given to use

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Answer 1

c) ) Sloke Slope (m) of the giver m=-11€ (-) -3 -1 line AB is - ma dz-2, 7 [math -14 7147 = 7 3) Equation of the line AB is g=mute where mz sope. ca constant ere m=st and it basses through the point A (11,-1) ' I = 11X54C 76=-1-58/7 = = 62 - The only required equation of the line AB is y = 514 6/ 354-494-23420 is, ty = 54-62 3/4+254 + 10 20 T-744-44420 po 52- ty -62307-012 6 1507746-62206 e sn= 62542 0 =42 1726 37 Slone (ml) of the line not that is berpendiculan to AD is) (mL = F 7/5 on=foo 4 4] . y = -7/5nte which is bosses through P(-1,0) i e =1+7/5(-) = -2 Therefore perpendicular line of AB is - y = -7/5- 2/5 dy tutay+220) ② Point of intersection of the lire and ② is 8 (4,-6) 6 Distance between the post P(-1,1) and the point 8 (4,-6) Vs I Distance fannula d = JE6-17 L4 tigh darby to the = √49125 = 1874 Unitz