Question

S3) Cooling tower made of concrete material, having a length of 360 m and constant thickness of 2 m, carries its own weight. In addition, it is assumed that a constant wind force of q = 2 kN/m affects the tower horizontally from left to right through the height of the tower. The outer diameter of the tower varies depending on x as d = 20 - 0.1 x+0.00035 x? , where d and x are in meters. The specific weight of the concrete is 24 kN/m². According to this; (a) Find the values of the cross-section effects affecting on the cross section of tower at the height of 180 m. Show these cross-section effects on the cross section in the correct directions in accordance with the axis set. (b) Find the maximum normal stress that occurs on the cross section at the height of 180 m. 9 = 2 kN/m 360 m

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Answer 1

Solution in sy x بارے Zoom TIL Given data: - tength 'L': 360m ; thickneld 't's 2m q* 2 kN/m weight of the concretes - 24 kN/m3 Diameter & height relation as givens the questions, a.) in É da 20- 0.17 + 0.0003 5042 Where, at els couter diameter. And area of cross-section depends on óe', @ 180 m d = 20- Olot 0.0003 572 d = 20- 01X180+0.00035 x (180) 2 da 13034 m Let thicknees is "ta di= dot. ? 13:34 - 218 11.34 m

b.) Here, normal stress occur due to self- weight of the concrete. Cantilever beam of the varying erohf-feetion with uniformly distributed load. Area moment of inertia =J consides a small element at distance a having thickneus dr. da = aardr loco - * (dot-dit) 64 At 180 m, do = 13034m, di = 11.34 m Ixx = * ((13.34)4- (11.3454) 64 19090 = 742, 759 m4 Now, Normal strees = oba M max oy Mmax = Ixx 9.22 5) 2x107x(180) 32400 KNM 2 2 Sь: 32400 x103 x 1 742-759 ( 9 - 1/2 - 2- 3) Hence, maximum roronal Stress occurs on the els at height 180m e 43.621 kPa. ob 45.621 kPa
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