help with #1 please 1) How many moles of NaOH would you need to neutralize 50.0...

Question

Question

help with #1 please

Answer 1

Answer #1

We know that,

For neutralization reaction,

Number of moles of acid= Number of moles of base

i.e.

n(base) = n(acid)

n(NaOH) = MV/1000

n(NaOH) = 0.250×50.0/1000

n(NaOH) = 0.0125 moles

Answer 2

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