Part A
Estimate the number of moles of water in all the Earth's oceans. Assume water covers 75% of the Earth to an average depth of 3 km.
Express your answer to one significant figures and include the appropriate units.
Part B
Estimate the number of molecules of water in all the Earth's oceans.
Express your answer using one significant figure.
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Part A.
We know that:
Molecular weight of water = 18 gm/mol = 18*10^-3 kg/mol
Number of moles = mass/Molecular weight
Mass of all the water on earth will be:
Mass = density*Volume
density of sea water = 1025 kg/m^3
Volume of water = 75% of Surface area of earth*depth of water = 0.75*4*pi*R^2*h
R = radius of earth = 6.371*10^6 m
h = depth of water = 3 km = 3000 m
So,
Volume = 0.75*4*pi*(6.371*10^6)^2*3000 = 1.1476*10^18 m^3
So,
Mass = 1025*1.1476*10^18 = 1.176*10^21 kg
Number of moles will be:
n = m/Mw
n = 1.176*10^21/(18*10^-3)
n = 6.533*10^22 moles
In one significant figures:
n = 7*10^22 moles
Part B.
Number of molecules of water will be:
N = n*Na
Na = Avogadro's number = 6.02*10^23 molescules
So,
N = 6.533*10^22*6.02*10^23
N = 3.933*10^46 molecules
In one signifcant figures:
N = 4*10^46 molecules
Let me know if you've any query.
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