2a) Integrated form of first orde rate equation is
ln[A]t = -kt + ln[A]0
Where, k = rate constant , 1.42 × 10^-4/s
ln[A]t = concentration at time t , 0.65M
ln[A]0 = concentration at initial, 1M
t = time , ?
Substituting the values
ln(0.65M) = - (1.42 ×10^-4/s)×t + ln(1M)
t = - ln(0.65) s /1.42 × 10^-4
= 3034 seconds
2b) Initial concentration , [A]0 is 0.150MM
[A]t = ? , t = 30seconds , k=1.42×10^-4/s
Substituting the values,
ln[A] = - (1.42 × 10^-4/s) × 300 s + ln(0.150M)
2.303log[A] = - 0.0426 - 1.8975M
[A] = 0.144M
3.Integrated form of second order equation is
1/[A]t = kt + 1/[A]0
k =7.02 × 10^-3 /M s
[A]0 = 0.125M , t = 350 seconds
[A]t = ?
Substituting the values
1/[A]t = ( 7.02 ×10^-3/M s )× 350s + 1/0.125M
= 0.0956M
the decomposition of so2cl2 with a rate Need help. Don't understand CHM 1046 2. The decomposition...
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