Answer a= X1= number of 5 lb bags of puppy blend produced
X2= number of 5 lb bags of adult blend produced
X3= number of 5 lb bags of geriatric blend produced
Objective function= It is to maximize the production
Max Z= X1+X2+X3
Subjected to=
Demand for puppy blend = X1≤2000
Demand for adult blend = X2≤8000
Demand for geriatric blend = X3≤1000
Chicken availability =2.5 X1+1.5X2+X3 ≤10000
Fish availability = X1+2 X2+2 X3 ≤20000
Soya flour availability =0.5 X1+0.5 X2+X3 ≤5000
Answer 2 b= The new objective function wil be to maximize the prfit earned from the production of all three products
Maximize: z = 9.5x1 + 8.5x2 + 9x3-2.5 (2.5x1 + 1.5x2 + x3) -1.5 (x1 + 2x2 + 2x3) -2 (0.5x1 + 0.5x2 + x3)
where
the amount of chicken used to prepare all dog food bags =(2.5x1 + 1.5x2 + x3)
the amount of fish meal used to prepare all dog food bag= (x1 + 2x2 + 2x3) is
the amount of soy flour used to prepare all dog food bags =(0.5x1 + 0.5x2 + x3)
Maximize: z = (9.5 - 2.5*2.5 - 1.5*1 - 2*0.5) *1 +( 8.5 - 2.5*1.5 - 1.5*2 - 2 *0.5) *2 +( 9 - 2.5*1 - 1.5*2 - 2 *1) *3
Maximize: z = 0.75 x1 - 1.25 x2 + 1.5 x3
b. Reformulate the linear programming model if the company is now interested in maximizing their profit...
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