1.3 length of the 1.2 The equation PwfVog+ po(1 - ) Vog = poVog models the...

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Question

1.3

Answer 1

Answer #1

we have the equation as

$\frac{1}{2}mv_0^2=mgl\sin \theta+\frac{1}{2}kl^2$

solving for inclination $\theta$ ,

$mgl\sin \theta=\frac{1}{2}(mv_0^2-kl^2)$

$\sin \theta=\frac{1}{2mgl}(mv_0^2-kl^2)$

$\sin \theta=\frac{v_0^2}{2gl}-\frac{kl}{2mg}$

$\boldsymbol{\theta=\sin^{-1}(\frac{v_0^2}{2gl}-\frac{kl}{2mg})}$

Answer 2

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