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A spring has a natural length of 22 cm. If a 28-N force is required to keep it stretched to a length of 40 cm, how much work

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In this question first we calculate the spring constant from the given condition. Then we have find the work done using integration. Hope you understand the solution.

ce solution) Given natural length of spring it 22cm 28 N force is required to keep it stretched to a tength of 40cm we need tF=kDx Dx= 40-22 = 18 cm Dx = 0.18m k= 28 - = 155.55 N 0.18 Ke 155.55 N m. work done Now we need to streetch 22 to find to 31cWork is given by on W I F da our limit will - become and x = 0.09 = 0.31-0.22 ?, = 0 0.09 W = kx dx 0.09 WE * [*] WE 155.55x1Thank you

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