Question

. -1 points SerPSE9 20.P.011.MI.FB ty Notes O Ask A 1.s0-kg iron horseshoe initially at 630°C is dropped into a bucket containing 25.0 kg of water at 24.0°C, what is the final temperature of the watar-horseshoe system? Ignore the heat capacity of the contaner and assume a negligible amount of water boils away. Need Help? Lean -11 rol

Answer 1

Heat lost by iron = Heat gained by water

    M C dt = m C ' dT ---(1)

where M = mass of iron = 1.5 kg

            C = specific heat of iron =  449 J/(kg.K)

          dt = temperature difference = 630 - T

           m = mass of water = 25 kg

           C ' = specific heat of water = 4186 J / kg K

          dT = T - 24

Put the values in the equation 1 ,you will get the value of T

            T = final temperature